Difference between revisions of "Talk:Body fat excess"
From Bioblast
Line 1: | Line 1: | ||
''Work in progress'' | ''Work in progress'' | ||
=== Body fat in the healthy reference population - | === Body fat in the healthy reference population - a complementary route === | ||
:::: | :::: In turn, ''M'' is the sum of the reference mass at a given height and excess body mass, ''M''<sub>E</sub> <big>≝</big> ''M''-''M''°(Eq. 3). Excess body mass, ''M''<sub>E</sub>, is due to accumulation of an excess fat mass, ''M''<sub>FE</sub>, accompanied by a gain of excess lean mass, ''M''<sub>LE</sub>, which . Thus Eq. 13 and 2 combined yield the definition for excess body mass, ''M''<sub>E</sub> <big>≝</big> ''M''<sub>FE</sub> + ''M''<sub>LE</sub></big> (Eq. 4). | ||
:::: Inserting Eq. 4 into Eq. 3, | |||
<big>'''Eq. 13''': ''M'' = ''M''° + ''M''<sub>FE</sub> + ''M''<sub>LE</sub></big> | |||
<big>'''Eq. | |||
:::: The fat mass, ''M''<sub>F</sub>, is defined as the sum of the reference fat mass and excess fat mass, ''M''<sub>F</sub> <big>≝</big> ''M''°<sub>F</sub>+''M''<sub>FE, hence | :::: The fat mass, ''M''<sub>F</sub>, is defined as the sum of the reference fat mass and excess fat mass, ''M''<sub>F</sub> <big>≝</big> ''M''°<sub>F</sub>+''M''<sub>FE, hence | ||
<big>'''Eq. | <big>'''Eq. 14''': ''M''<sub>FE</sub> <big>≝</big> ''M''<sub>F</sub> - ''M''°<sub>F</sub></big> | ||
:::: Inserting Eq. 14 into Eq. 13 yields body mass as the sum of the reference mass minus reference fat mass (which is the reference lean mass, ''M''°<sub>L</sub> = ''M''-''M''°<sub>F</sub>), plus the total body fat mass and the excess lean mass, | |||
: | <big>'''Eq. 15''': ''M'' = ''M''° + ''M''<sub>F</sub> - ''M''°<sub>F</sub> + ''M''<sub>LE</sub></big> | ||
:::: Normalization of Eq. 15 for ''M''° and considering that the [[body mass excess]] is BME=''M''/''M''°-1 (Eq. 5a), BFE = (''M''<sub>F</sub>-''M''°<sub>F</sub>)/''M''° (Eq. 5b), and BLE = ''M''<sub>LE</sub></big>/''M''° (Eq. 5c), yields Eq. 7 in the form of, | |||
<big>'''Eq. 16''': BME = BFE + BLE</big> | |||
:::: By further normalization of Eq. 16 for BME, we obtain the summation of ''f''<sub>FE</sub> = BFE/BME (Eq. 9) and ''f''<sub>LE</sub> = BLE/BME (Eq. 10), | |||
: | <big>'''Eq. 17''': 1 = ''f''<sub>FE</sub> + ''f''<sub>LE</sub> | ||
:::: where ''f''<sub>FE</sub> = 0.57 is the slope in Fig. 5b. | |||
:::: which | :::: To derive the ''M''<sub>LE</sub>/''M''<sub>FE</sub> ratio (Eq. 12), which is equal to BLE/BFE (Eq. 5b and 5c), Eq. 16 is divided by BFE and rearranged, | ||
<big>'''Eq. 18''': BLE/BFE = BME/BFE - 1</big> | |||
:::: | :::: Eq. 18 is equivalent to Eq. 12, since BME/BFE = ''f''<sub>FE</sub> (Eq. 9). |
Revision as of 18:22, 17 January 2020
Work in progress
Body fat in the healthy reference population - a complementary route
- In turn, M is the sum of the reference mass at a given height and excess body mass, ME ≝ M-M°(Eq. 3). Excess body mass, ME, is due to accumulation of an excess fat mass, MFE, accompanied by a gain of excess lean mass, MLE, which . Thus Eq. 13 and 2 combined yield the definition for excess body mass, ME ≝ MFE + MLE (Eq. 4).
- Inserting Eq. 4 into Eq. 3,
Eq. 13: M = M° + MFE + MLE
- The fat mass, MF, is defined as the sum of the reference fat mass and excess fat mass, MF ≝ M°F+MFE, hence
Eq. 14: MFE ≝ MF - M°F
- Inserting Eq. 14 into Eq. 13 yields body mass as the sum of the reference mass minus reference fat mass (which is the reference lean mass, M°L = M-M°F), plus the total body fat mass and the excess lean mass,
Eq. 15: M = M° + MF - M°F + MLE
- Normalization of Eq. 15 for M° and considering that the body mass excess is BME=M/M°-1 (Eq. 5a), BFE = (MF-M°F)/M° (Eq. 5b), and BLE = MLE/M° (Eq. 5c), yields Eq. 7 in the form of,
Eq. 16: BME = BFE + BLE
- By further normalization of Eq. 16 for BME, we obtain the summation of fFE = BFE/BME (Eq. 9) and fLE = BLE/BME (Eq. 10),
Eq. 17: 1 = fFE + fLE
- where fFE = 0.57 is the slope in Fig. 5b.
- To derive the MLE/MFE ratio (Eq. 12), which is equal to BLE/BFE (Eq. 5b and 5c), Eq. 16 is divided by BFE and rearranged,
Eq. 18: BLE/BFE = BME/BFE - 1
- Eq. 18 is equivalent to Eq. 12, since BME/BFE = fFE (Eq. 9).